2x^2-7x=160

Solution for 2x^2-7x=160 equation:

2x^2-7x=160

We move all terms to the left:

2x^2-7x-(160)=0

a = 2; b = -7; c = -160;
Δ = b2-4ac
Δ = -72-4·2·(-160)
Δ = 1329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{1329}}{2*2}=\frac{7-\sqrt{1329}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{1329}}{2*2}=\frac{7+\sqrt{1329}}{4}
$